What are the solutions to the equation -5(2x-20)(15+5x)=0 ?

The solutions to the equation -5(2x-20)(15+5x)=0 are x=10,x=-3

Find the zeros of -5(2x-20)(15+5x)=0

The zeros of -5(2x-20)(15+5x)=0 are x=10,x=-3

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- 5 (2 x - 20) (15 + 5 x) = 0

x = 10, x = - 3

Solution steps

- 5 (2 x - 20) (15 + 5 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 20 = 0 or 15 + 5 x = 0

Solve

2 x - 20 = 0 : x = 10

Solve

15 + 5 x = 0 : x = - 3

The solutions to the quadratic equation are:

x = 10, x = - 3

4 x^{2} - 2 x = - 5

x^{2} + 5 = 10

4 x^{2} - 16 x = - 16

x^{2} + 5 = 54

x^{2} + 4 x - 240 = 0

What are the solutions to the equation -5(2x-20)(15+5x)=0 ?
The solutions to the equation -5(2x-20)(15+5x)=0 are x=10,x=-3
Find the zeros of -5(2x-20)(15+5x)=0
The zeros of -5(2x-20)(15+5x)=0 are x=10,x=-3