What are the solutions to the equation 3x^2+11x-15=0 ?

The solutions to the equation 3x^2+11x-15=0 are x=(-11+sqrt(301))/6 ,x=(-11-sqrt(301))/6

Find the zeros of 3x^2+11x-15=0

The zeros of 3x^2+11x-15=0 are x=(-11+sqrt(301))/6 ,x=(-11-sqrt(301))/6

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3 x^{2} + 11 x - 15 = 0

x = \frac{- 11 + 301}{6}, x = \frac{- 11 - 301}{6}

Decimal Notation

x = 1.05822 \dots, x = - 4.72489 \dots

Solution steps

3 x^{2} + 11 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 3 ( - 15 )}{2 \cdot 3}

1 1^{2} - 4 \cdot 3 (- 15) = 301

x_{1, 2} = \frac{- 11 \pm 301}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 11 + 301}{2 \cdot 3}, x_{2} = \frac{- 11 - 301}{2 \cdot 3}

x = \frac{- 11 + 301}{2 \cdot 3} : \frac{- 11 + 301}{6}

x = \frac{- 11 - 301}{2 \cdot 3} : \frac{- 11 - 301}{6}

The solutions to the quadratic equation are:

x = \frac{- 11 + 301}{6}, x = \frac{- 11 - 301}{6}

7 q^{2} + 6 q + 3 = 6 q^{2}

x^{2} + 9 x + 35 = 0

x^{2} + 2 x = 28

9 p^{2} + 6 p + 1 = 12

x^{2} = 9 x + 2

What are the solutions to the equation 3x^2+11x-15=0 ?
The solutions to the equation 3x^2+11x-15=0 are x=(-11+sqrt(301))/6 ,x=(-11-sqrt(301))/6
Find the zeros of 3x^2+11x-15=0
The zeros of 3x^2+11x-15=0 are x=(-11+sqrt(301))/6 ,x=(-11-sqrt(301))/6