What are the solutions to the equation (6b-8)^2-19=0 ?

The solutions to the equation (6b-8)^2-19=0 are b=(sqrt(19)+8)/6 ,b=(-sqrt(19)+8)/6

Find the zeros of (6b-8)^2-19=0

The zeros of (6b-8)^2-19=0 are b=(sqrt(19)+8)/6 ,b=(-sqrt(19)+8)/6

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(6 b - 8)^{2} - 19 = 0

b = \frac{19 + 8}{6}, b = \frac{- 19 + 8}{6}

Decimal Notation

b = 2.05981 \dots, b = 0.60685 \dots

Solution steps

(6 b - 8)^{2} - 19 = 0

Move

19

to the right side

(6 b - 8)^{2} = 19

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

6 b - 8 = 19 : b = \frac{19 + 8}{6}

Solve

6 b - 8 = - 19 : b = \frac{- 19 + 8}{6}

The solutions to the quadratic equation are:

b = \frac{19 + 8}{6}, b = \frac{- 19 + 8}{6}

8 x^{2} - 2 x = 15

3 x^{2} - 15 = 33

3 v^{2} - 18 v - 48 = 0

3 x^{2} + 5 x - 2 = 0

5 x^{2} - 10 x = 15

What are the solutions to the equation (6b-8)^2-19=0 ?
The solutions to the equation (6b-8)^2-19=0 are b=(sqrt(19)+8)/6 ,b=(-sqrt(19)+8)/6
Find the zeros of (6b-8)^2-19=0
The zeros of (6b-8)^2-19=0 are b=(sqrt(19)+8)/6 ,b=(-sqrt(19)+8)/6