What are the solutions to the equation 2(x+6)^2-41=-21 ?

The solutions to the equation 2(x+6)^2-41=-21 are x=sqrt(10)-6,x=-sqrt(10)-6

Find the zeros of 2(x+6)^2-41=-21

The zeros of 2(x+6)^2-41=-21 are x=sqrt(10)-6,x=-sqrt(10)-6

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2 (x + 6)^{2} - 41 = - 21

x = 10 - 6, x = - 10 - 6

Decimal Notation

x = - 2.83772 \dots, x = - 9.16227 \dots

Solution steps

2 (x + 6)^{2} - 41 = - 21

Move

41

to the right side

2 (x + 6)^{2} = 20

Divide both sides by

2

(x + 6)^{2} = 10

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 6 = 10 : x = 10 - 6

Solve

x + 6 = - 10 : x = - 10 - 6

The solutions to the quadratic equation are:

x = 10 - 6, x = - 10 - 6

5 - x^{2} = \frac{1}{4} x^{2}

12 x^{2} - 104 x + 153 = 0

6 x^{2} + 25 x + 25 = 0

5 y^{2} + 7 y - 3 = 4 y

x^{2} = \frac{3}{250}

What are the solutions to the equation 2(x+6)^2-41=-21 ?
The solutions to the equation 2(x+6)^2-41=-21 are x=sqrt(10)-6,x=-sqrt(10)-6
Find the zeros of 2(x+6)^2-41=-21
The zeros of 2(x+6)^2-41=-21 are x=sqrt(10)-6,x=-sqrt(10)-6