What are the solutions to the equation completesquare x^2+8x+41 ?

The solutions to the equation completesquare x^2+8x+41 are (x+4)^2+25

Find the zeros of completesquare x^2+8x+41

The zeros of completesquare x^2+8x+41 are (x+4)^2+25

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complete the square

x^{2} + 8 x + 41

(x + 4)^{2} + 25

Solution steps

x^{2} + 8 x + 41

Write

x^{2} + 8 x + 41

in the form:

x^{2} + 2 a x + a^{2}

2 a = 8 : a = 4

Add and subtract

4^{2}

x^{2} + 8 x + 41 + 4^{2} - 4^{2}

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} + 8 x + 4^{2} = (x + 4)^{2}

(x + 4)^{2} + 41 - 4^{2}

Simplify

(x + 4)^{2} + 25

x^{2} + x + \frac{1}{3} = \frac{2}{3}

12 x = 100 x^{2} - 2 \times 9.8 \times 5

- 2 x^{2} - 5 x = 7

s^{2} + 2 s - 6 = 0

3 p (5 p - 1) = 0

What are the solutions to the equation completesquare x^2+8x+41 ?
The solutions to the equation completesquare x^2+8x+41 are (x+4)^2+25
Find the zeros of completesquare x^2+8x+41
The zeros of completesquare x^2+8x+41 are (x+4)^2+25