What are the solutions to the equation 2x^2-x=0 ?

The solutions to the equation 2x^2-x=0 are x= 1/2 ,x=0

Find the zeros of 2x^2-x=0

The zeros of 2x^2-x=0 are x= 1/2 ,x=0

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2 x^{2} - x = 0

x = \frac{1}{2}, x = 0

Decimal Notation

x = 0.5, x = 0

Solution steps

2 x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 2}

x = \frac{- ( - 1 ) + 1}{2 \cdot 2} : \frac{1}{2}

x = \frac{- ( - 1 ) - 1}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 0

6 k^{2} \cdot k

2 x + 7 - 5 x + 8 = 3 (5 + 6 x) - 12 x

6 x - 18 = 14 x + 38

- 9 + 2 > 18 and 13 x + 15 \leq - 4

4 (x - 3) - 5 (x + 2) = 7 (3 x - 1) + 29

What are the solutions to the equation 2x^2-x=0 ?
The solutions to the equation 2x^2-x=0 are x= 1/2 ,x=0
Find the zeros of 2x^2-x=0
The zeros of 2x^2-x=0 are x= 1/2 ,x=0