What are the solutions to the equation x^2+0.6x-19.1=0 ?

The solutions to the equation x^2+0.6x-19.1=0 are x=(-3+sqrt(1919))/(10),x=-(3+sqrt(1919))/(10)

Find the zeros of x^2+0.6x-19.1=0

The zeros of x^2+0.6x-19.1=0 are x=(-3+sqrt(1919))/(10),x=-(3+sqrt(1919))/(10)

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x^{2} + 0.6 x - 19.1 = 0

x = \frac{- 3 + 1919}{10}, x = - \frac{3 + 1919}{10}

Decimal Notation

x = 4.08063 \dots, x = - 4.68063 \dots

Solution steps

x^{2} + 0.6 x - 19.1 = 0

Multiply both sides by

10

10 x^{2} + 6 x - 191 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 10 ( - 191 )}{2 \cdot 10}

6^{2} - 4 \cdot 10 (- 191) = 21919

x_{1, 2} = \frac{- 6 \pm 2 1919}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 6 + 2 1919}{2 \cdot 10}, x_{2} = \frac{- 6 - 2 1919}{2 \cdot 10}

x = \frac{- 6 + 2 1919}{2 \cdot 10} : \frac{- 3 + 1919}{10}

x = \frac{- 6 - 2 1919}{2 \cdot 10} : - \frac{3 + 1919}{10}

The solutions to the quadratic equation are:

x = \frac{- 3 + 1919}{10}, x = - \frac{3 + 1919}{10}

y, x^{2} + x y + y^{2} = 48

x (x - 3) = 5

x^{2} - x + 42 = 0

3 x^{2} + 15 x = 0

2 x^{2} + 5 x + 6 = - 2 x

What are the solutions to the equation x^2+0.6x-19.1=0 ?
The solutions to the equation x^2+0.6x-19.1=0 are x=(-3+sqrt(1919))/(10),x=-(3+sqrt(1919))/(10)
Find the zeros of x^2+0.6x-19.1=0
The zeros of x^2+0.6x-19.1=0 are x=(-3+sqrt(1919))/(10),x=-(3+sqrt(1919))/(10)