What are the solutions to the equation roots x^2-8x-1 ?

The solutions to the equation roots x^2-8x-1 are x=4+sqrt(17),x=4-sqrt(17)

Find the zeros of roots x^2-8x-1

The zeros of roots x^2-8x-1 are x=4+sqrt(17),x=4-sqrt(17)

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roots

x^{2} - 8 x - 1

x = 4 + 17, x = 4 - 17

Solution steps

x^{2} - 8 x - 1

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 8 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 1) = 217

x_{1, 2} = \frac{- ( - 8 ) \pm 2 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 17}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 17}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 17}{2 \cdot 1} : 4 + 17

x = \frac{- ( - 8 ) - 2 17}{2 \cdot 1} : 4 - 17

The solutions to the quadratic equation are:

x = 4 + 17, x = 4 - 17

4 p^{2} - 1 = - 2

\frac{x ^{2}}{81} - 6 = - 2

m^{2} = 0.09

- 8 x^{2} - 3 x + 22 = 0

x^{2} - 6 x + 2

What are the solutions to the equation roots x^2-8x-1 ?
The solutions to the equation roots x^2-8x-1 are x=4+sqrt(17),x=4-sqrt(17)
Find the zeros of roots x^2-8x-1
The zeros of roots x^2-8x-1 are x=4+sqrt(17),x=4-sqrt(17)