What are the solutions to the equation 2y^2-y+1=0 ?

The solutions to the equation 2y^2-y+1=0 are y= 1/4+i(sqrt(7))/4 ,y= 1/4-i(sqrt(7))/4

Find the zeros of 2y^2-y+1=0

The zeros of 2y^2-y+1=0 are y= 1/4+i(sqrt(7))/4 ,y= 1/4-i(sqrt(7))/4

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2 y^{2} - y + 1 = 0

y = \frac{1}{4} + i \frac{7}{4}, y = \frac{1}{4} - i \frac{7}{4}

Solution steps

2 y^{2} - y + 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

Simplify

(- 1)^{2} - 4 \cdot 2 \cdot 1 : 7 i

y_{1, 2} = \frac{- ( - 1 ) \pm 7 i}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 7 i}{2 \cdot 2}, y_{2} = \frac{- ( - 1 ) - 7 i}{2 \cdot 2}

y = \frac{- ( - 1 ) + 7 i}{2 \cdot 2} : \frac{1}{4} + i \frac{7}{4}

y = \frac{- ( - 1 ) - 7 i}{2 \cdot 2} : \frac{1}{4} - i \frac{7}{4}

The solutions to the quadratic equation are:

y = \frac{1}{4} + i \frac{7}{4}, y = \frac{1}{4} - i \frac{7}{4}

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2 (3 x + 9)^{2} = 50

y, x^{2} + 4 x y + 8 y^{2} = 20

7 x^{2} + 14 x = - 7

What are the solutions to the equation 2y^2-y+1=0 ?
The solutions to the equation 2y^2-y+1=0 are y= 1/4+i(sqrt(7))/4 ,y= 1/4-i(sqrt(7))/4
Find the zeros of 2y^2-y+1=0
The zeros of 2y^2-y+1=0 are y= 1/4+i(sqrt(7))/4 ,y= 1/4-i(sqrt(7))/4