What are the solutions to the equation 20^2+14^2=z^2 ?

The solutions to the equation 20^2+14^2=z^2 are z=2sqrt(149),z=-2sqrt(149)

Find the zeros of 20^2+14^2=z^2

The zeros of 20^2+14^2=z^2 are z=2sqrt(149),z=-2sqrt(149)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 0^{2} + 1 4^{2} = z^{2}

z = 2149, z = - 2149

Decimal Notation

z = 24.41311 \dots, z = - 24.41311 \dots

Solution steps

2 0^{2} + 1 4^{2} = z^{2}

Switch sides

z^{2} = 2 0^{2} + 1 4^{2}

Simplify

2 0^{2} + 1 4^{2} : 596

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = 596, z = - 596

596 = 2149

- 596 = - 2149

z = 2149, z = - 2149

110 - p^{2} = p

10 x^{2} + 9 x + 2 = 0

2 W^{2} + 5 W - 63 = 0

x^{2} - 10 x + 16

y^{2} - 6 y - 27 = 0

What are the solutions to the equation 20^2+14^2=z^2 ?
The solutions to the equation 20^2+14^2=z^2 are z=2sqrt(149),z=-2sqrt(149)
Find the zeros of 20^2+14^2=z^2
The zeros of 20^2+14^2=z^2 are z=2sqrt(149),z=-2sqrt(149)