What are the solutions to the equation -x(x-1)=3 ?

The solutions to the equation -x(x-1)=3 are x= 1/2-i(sqrt(11))/2 ,x= 1/2+i(sqrt(11))/2

Find the zeros of -x(x-1)=3

The zeros of -x(x-1)=3 are x= 1/2-i(sqrt(11))/2 ,x= 1/2+i(sqrt(11))/2

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- x (x - 1) = 3

x = \frac{1}{2} - i \frac{11}{2}, x = \frac{1}{2} + i \frac{11}{2}

Solution steps

- x (x - 1) = 3

Expand

- x (x - 1) : - x^{2} + x

- x^{2} + x = 3

Move

3

to the left side

- x^{2} + x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) ( - 3 )}{2 ( - 1 )}

Simplify

1^{2} - 4 (- 1) (- 3) : 11 i

x_{1, 2} = \frac{- 1 \pm 11 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 11 i}{2 ( - 1 )}, x_{2} = \frac{- 1 - 11 i}{2 ( - 1 )}

x = \frac{- 1 + 11 i}{2 ( - 1 )} : \frac{1}{2} - i \frac{11}{2}

x = \frac{- 1 - 11 i}{2 ( - 1 )} : \frac{1}{2} + i \frac{11}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} - i \frac{11}{2}, x = \frac{1}{2} + i \frac{11}{2}

x^{2} - \frac{4}{5} x - 2 = 0

12 x^{2} - 272 x + 1035 = 0

10000 + 12 x + 0.001 x^{2} = 22 x - 0.0005 x^{2}

4 y^{2} + 4 y - 3 = 0

44 x^{2} - 556 x + 336 = 0

What are the solutions to the equation -x(x-1)=3 ?
The solutions to the equation -x(x-1)=3 are x= 1/2-i(sqrt(11))/2 ,x= 1/2+i(sqrt(11))/2
Find the zeros of -x(x-1)=3
The zeros of -x(x-1)=3 are x= 1/2-i(sqrt(11))/2 ,x= 1/2+i(sqrt(11))/2