What are the solutions to the equation factor 16x^2-49=0 ?

The solutions to the equation factor 16x^2-49=0 are x=-7/4 ,x= 7/4

Find the zeros of factor 16x^2-49=0

The zeros of factor 16x^2-49=0 are x=-7/4 ,x= 7/4

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16 x^{2} - 49 = 0

x = - \frac{7}{4}, x = \frac{7}{4}

Decimal Notation

x = - 1.75, x = 1.75

Solution steps

16 x^{2} - 49 = 0

Factor

16 x^{2} - 49 : (4 x + 7) (4 x - 7)

(4 x + 7) (4 x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 7 = 0 or 4 x - 7 = 0

Solve

4 x + 7 = 0 : x = - \frac{7}{4}

Solve

4 x - 7 = 0 : x = \frac{7}{4}

The solutions to the quadratic equation are:

x = - \frac{7}{4}, x = \frac{7}{4}

4 (10 - 3 x)^{2} - 4 = 5

(x + 8)^{2} = - 1

\frac{1}{2} x^{2} + 7 x + 20 = 0

(x - 2)^{2} = 10

5 x^{2} - 16 = 8 x

What are the solutions to the equation factor 16x^2-49=0 ?
The solutions to the equation factor 16x^2-49=0 are x=-7/4 ,x= 7/4
Find the zeros of factor 16x^2-49=0
The zeros of factor 16x^2-49=0 are x=-7/4 ,x= 7/4