What is the answer to solvefor y,xy+2x+3x^2=4 ?

The answer to solvefor y,xy+2x+3x^2=4 is y=(4-2x-3x^2)/x ;\quad x\ne 0

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solvefor y,xy+2x+3x^2=4

solve for

y, x y + 2 x + 3 x^{2} = 4

y = \frac{4 - 2 x - 3 x ^{2}}{x}; x \neq = 0

Solution steps

x y + 2 x + 3 x^{2} = 4

Move

2 x

to the right side

x y + 3 x^{2} = 4 - 2 x

Move

3 x^{2}

to the right side

x y = 4 - 2 x - 3 x^{2}

Divide both sides by

x; x \neq = 0

y = \frac{4 - 2 x - 3 x ^{2}}{x}; x \neq = 0

- 2 x^{2} - 4 x + 6

3 t^{2} - 16 t + 5 = 0

6 t = - 3 t^{2} + 75 t + 150

y, x^{2} - 12 x y + y^{2} = 70

0 = 2 x^{2} - 10 x

What is the answer to solvefor y,xy+2x+3x^2=4 ?
The answer to solvefor y,xy+2x+3x^2=4 is y=(4-2x-3x^2)/x ;\quad x\ne 0