What are the solutions to the equation -16=x^2-10x ?

The solutions to the equation -16=x^2-10x are x=8,x=2

Find the zeros of -16=x^2-10x

The zeros of -16=x^2-10x are x=8,x=2

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- 16 = x^{2} - 10 x

x = 8, x = 2

Solution steps

- 16 = x^{2} - 10 x

Switch sides

x^{2} - 10 x = - 16

Move

16

to the left side

x^{2} - 10 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 16 = 6

x_{1, 2} = \frac{- ( - 10 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 6}{2 \cdot 1}

x = \frac{- ( - 10 ) + 6}{2 \cdot 1} : 8

x = \frac{- ( - 10 ) - 6}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 8, x = 2

0 = 3 x^{2} + 4 x - 4

x^{2} + x a + a^{2}

- x^{2} - 0 x + 16 = 0

2 p^{2} + 2 p - 84 = 0

y, x^{2} y^{2} + x y = 12

What are the solutions to the equation -16=x^2-10x ?
The solutions to the equation -16=x^2-10x are x=8,x=2
Find the zeros of -16=x^2-10x
The zeros of -16=x^2-10x are x=8,x=2