What are the solutions to the equation x^2+3x-1000=0 ?

The solutions to the equation x^2+3x-1000=0 are x=(-3+sqrt(4009))/2 ,x=(-3-sqrt(4009))/2

Find the zeros of x^2+3x-1000=0

The zeros of x^2+3x-1000=0 are x=(-3+sqrt(4009))/2 ,x=(-3-sqrt(4009))/2

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x^{2} + 3 x - 1000 = 0

x = \frac{- 3 + 4009}{2}, x = \frac{- 3 - 4009}{2}

Decimal Notation

x = 30.15833 \dots, x = - 33.15833 \dots

Solution steps

x^{2} + 3 x - 1000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 1000 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 1000) = 4009

x_{1, 2} = \frac{- 3 \pm 4009}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 4009}{2 \cdot 1}, x_{2} = \frac{- 3 - 4009}{2 \cdot 1}

x = \frac{- 3 + 4009}{2 \cdot 1} : \frac{- 3 + 4009}{2}

x = \frac{- 3 - 4009}{2 \cdot 1} : \frac{- 3 - 4009}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 4009}{2}, x = \frac{- 3 - 4009}{2}

x^{2} + 16 x + 128 = 0

4 (3 x + 8)^{2} + 17 = 21

y, 2 (x^{2} + y^{2}) = 25 (x^{2} - y^{2})

12 x^{2} - 5 x - 2 = 0

s^{2} + 6 s + 13

What are the solutions to the equation x^2+3x-1000=0 ?
The solutions to the equation x^2+3x-1000=0 are x=(-3+sqrt(4009))/2 ,x=(-3-sqrt(4009))/2
Find the zeros of x^2+3x-1000=0
The zeros of x^2+3x-1000=0 are x=(-3+sqrt(4009))/2 ,x=(-3-sqrt(4009))/2