What are the solutions to the equation 2q^2+2q-1=0 ?

The solutions to the equation 2q^2+2q-1=0 are q=(-1+sqrt(3))/2 ,q=-(1+sqrt(3))/2

Find the zeros of 2q^2+2q-1=0

The zeros of 2q^2+2q-1=0 are q=(-1+sqrt(3))/2 ,q=-(1+sqrt(3))/2

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2 q^{2} + 2 q - 1 = 0

q = \frac{- 1 + 3}{2}, q = - \frac{1 + 3}{2}

Decimal Notation

q = 0.36602 \dots, q = - 1.36602 \dots

Solution steps

2 q^{2} + 2 q - 1 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 1) = 23

q_{1, 2} = \frac{- 2 \pm 2 3}{2 \cdot 2}

Separate the solutions

q_{1} = \frac{- 2 + 2 3}{2 \cdot 2}, q_{2} = \frac{- 2 - 2 3}{2 \cdot 2}

q = \frac{- 2 + 2 3}{2 \cdot 2} : \frac{- 1 + 3}{2}

q = \frac{- 2 - 2 3}{2 \cdot 2} : - \frac{1 + 3}{2}

The solutions to the quadratic equation are:

q = \frac{- 1 + 3}{2}, q = - \frac{1 + 3}{2}

25 v^{2} - 9 = 0

- 2 x + 2 x^{2} = - 3

2 b^{2} + 12 b + 23 = 6

x = 2 x^{2} - 2 x + 3

25 x^{2} - 225 x = 0

What are the solutions to the equation 2q^2+2q-1=0 ?
The solutions to the equation 2q^2+2q-1=0 are q=(-1+sqrt(3))/2 ,q=-(1+sqrt(3))/2
Find the zeros of 2q^2+2q-1=0
The zeros of 2q^2+2q-1=0 are q=(-1+sqrt(3))/2 ,q=-(1+sqrt(3))/2