What are the solutions to the equation 2q^2+10q-9=0 ?

The solutions to the equation 2q^2+10q-9=0 are q=(-5+sqrt(43))/2 ,q=-(5+sqrt(43))/2

Find the zeros of 2q^2+10q-9=0

The zeros of 2q^2+10q-9=0 are q=(-5+sqrt(43))/2 ,q=-(5+sqrt(43))/2

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2 q^{2} + 10 q - 9 = 0

q = \frac{- 5 + 43}{2}, q = - \frac{5 + 43}{2}

Decimal Notation

q = 0.77871 \dots, q = - 5.77871 \dots

Solution steps

2 q^{2} + 10 q - 9 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 (- 9) = 243

q_{1, 2} = \frac{- 10 \pm 2 43}{2 \cdot 2}

Separate the solutions

q_{1} = \frac{- 10 + 2 43}{2 \cdot 2}, q_{2} = \frac{- 10 - 2 43}{2 \cdot 2}

q = \frac{- 10 + 2 43}{2 \cdot 2} : \frac{- 5 + 43}{2}

q = \frac{- 10 - 2 43}{2 \cdot 2} : - \frac{5 + 43}{2}

The solutions to the quadratic equation are:

q = \frac{- 5 + 43}{2}, q = - \frac{5 + 43}{2}

x^{2} - 20 x + 90 = 0

2 y^{2} - 3 y - 9 = 0

x^{2} - 14 x - 11 = - 30

(x + 1)^{2} - 1 \frac{1}{3} = 0

x, (x + 8)^{2} = 16

What are the solutions to the equation 2q^2+10q-9=0 ?
The solutions to the equation 2q^2+10q-9=0 are q=(-5+sqrt(43))/2 ,q=-(5+sqrt(43))/2
Find the zeros of 2q^2+10q-9=0
The zeros of 2q^2+10q-9=0 are q=(-5+sqrt(43))/2 ,q=-(5+sqrt(43))/2