What are the solutions to the equation -2x^2+4x+6=15 ?

The solutions to the equation -2x^2+4x+6=15 are x=1-isqrt(7/2),x=1+isqrt(7/2)

Find the zeros of -2x^2+4x+6=15

The zeros of -2x^2+4x+6=15 are x=1-isqrt(7/2),x=1+isqrt(7/2)

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- 2 x^{2} + 4 x + 6 = 15

x = 1 - i \frac{7}{2}, x = 1 + i \frac{7}{2}

Solution steps

- 2 x^{2} + 4 x + 6 = 15

Move

15

to the left side

- 2 x^{2} + 4 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) ( - 9 )}{2 ( - 2 )}

Simplify

4^{2} - 4 (- 2) (- 9) : 214 i

x_{1, 2} = \frac{- 4 \pm 2 14 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 14 i}{2 ( - 2 )}, x_{2} = \frac{- 4 - 2 14 i}{2 ( - 2 )}

x = \frac{- 4 + 2 14 i}{2 ( - 2 )} : 1 - i \frac{7}{2}

x = \frac{- 4 - 2 14 i}{2 ( - 2 )} : 1 + i \frac{7}{2}

The solutions to the quadratic equation are:

x = 1 - i \frac{7}{2}, x = 1 + i \frac{7}{2}

x^{2} + 3 x = a x + 3 a

y, 3 x^{2} + 8 x y + 9 y^{2} = 6

5 a^{2} - 100 = 0

2 x^{2} + 192 = 40 x

X^{2} = 3 X + 4

What are the solutions to the equation -2x^2+4x+6=15 ?
The solutions to the equation -2x^2+4x+6=15 are x=1-isqrt(7/2),x=1+isqrt(7/2)
Find the zeros of -2x^2+4x+6=15
The zeros of -2x^2+4x+6=15 are x=1-isqrt(7/2),x=1+isqrt(7/2)