What are the solutions to the equation x^2+7x=-3 ?

The solutions to the equation x^2+7x=-3 are x=(-7+sqrt(37))/2 ,x=(-7-sqrt(37))/2

Find the zeros of x^2+7x=-3

The zeros of x^2+7x=-3 are x=(-7+sqrt(37))/2 ,x=(-7-sqrt(37))/2

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x^{2} + 7 x = - 3

x = \frac{- 7 + 37}{2}, x = \frac{- 7 - 37}{2}

Decimal

x = - 0.45861 \dots, x = - 6.54138 \dots

Solution steps

x^{2} + 7 x = - 3

Move

3

to the left side

x^{2} + 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 3 = 37

x_{1, 2} = \frac{- 7 \pm 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 37}{2 \cdot 1}, x_{2} = \frac{- 7 - 37}{2 \cdot 1}

x = \frac{- 7 + 37}{2 \cdot 1} : \frac{- 7 + 37}{2}

x = \frac{- 7 - 37}{2 \cdot 1} : \frac{- 7 - 37}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 37}{2}, x = \frac{- 7 - 37}{2}

3 q^{2} + 128 q - 600 = 0

x^{2} - 5 x - 40 = 0

x^{2} + 5 x + 11 = 13 x

2 W^{2} - 3 W - 27 = 0

r^{2} - r - 11 = 0

What are the solutions to the equation x^2+7x=-3 ?
The solutions to the equation x^2+7x=-3 are x=(-7+sqrt(37))/2 ,x=(-7-sqrt(37))/2
Find the zeros of x^2+7x=-3
The zeros of x^2+7x=-3 are x=(-7+sqrt(37))/2 ,x=(-7-sqrt(37))/2