What are the solutions to the equation solvefor x,(x-a)^2+y^2=a^2 ?

The solutions to the equation solvefor x,(x-a)^2+y^2=a^2 are x=sqrt(a^2-y^2)+a,x=-sqrt(a^2-y^2)+a

Find the zeros of solvefor x,(x-a)^2+y^2=a^2

The zeros of solvefor x,(x-a)^2+y^2=a^2 are x=sqrt(a^2-y^2)+a,x=-sqrt(a^2-y^2)+a

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solve for

x, (x - a)^{2} + y^{2} = a^{2}

x = a^{2} - y^{2} + a, x = - a^{2} - y^{2} + a

Solution steps

(x - a)^{2} + y^{2} = a^{2}

Move

y^{2}

to the right side

(x - a)^{2} = a^{2} - y^{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - a = a^{2} - y^{2} : x = a^{2} - y^{2} + a

Solve

x - a = - a^{2} - y^{2} : x = - a^{2} - y^{2} + a

The solutions to the quadratic equation are:

x = a^{2} - y^{2} + a, x = - a^{2} - y^{2} + a

16.1 x^{2} + 18 x = 50

x^{2} n^{3} + x^{2} m^{3} + m^{5} n^{4}

(2 x + 2)^{2} + 5 = 1

y, x^{2} + x y - y^{2} = 0

y, x^{2} + x y - y^{2} = 1

What are the solutions to the equation solvefor x,(x-a)^2+y^2=a^2 ?
The solutions to the equation solvefor x,(x-a)^2+y^2=a^2 are x=sqrt(a^2-y^2)+a,x=-sqrt(a^2-y^2)+a
Find the zeros of solvefor x,(x-a)^2+y^2=a^2
The zeros of solvefor x,(x-a)^2+y^2=a^2 are x=sqrt(a^2-y^2)+a,x=-sqrt(a^2-y^2)+a