What are the solutions to the equation x^2+26x+167.5=0 ?

The solutions to the equation x^2+26x+167.5=0 are x=(-26+sqrt(6))/2 ,x=-(26+sqrt(6))/2

Find the zeros of x^2+26x+167.5=0

The zeros of x^2+26x+167.5=0 are x=(-26+sqrt(6))/2 ,x=-(26+sqrt(6))/2

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x^{2} + 26 x + 167.5 = 0

x = \frac{- 26 + 6}{2}, x = - \frac{26 + 6}{2}

Decimal Notation

x = - 11.77525 \dots, x = - 14.22474 \dots

Solution steps

x^{2} + 26 x + 167.5 = 0

Multiply both sides by

10

10 x^{2} + 260 x + 1675 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 260 \pm 26 0 ^{2} - 4 \cdot 10 \cdot 1675}{2 \cdot 10}

26 0^{2} - 4 \cdot 10 \cdot 1675 = 106

x_{1, 2} = \frac{- 260 \pm 10 6}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 260 + 10 6}{2 \cdot 10}, x_{2} = \frac{- 260 - 10 6}{2 \cdot 10}

x = \frac{- 260 + 10 6}{2 \cdot 10} : \frac{- 26 + 6}{2}

x = \frac{- 260 - 10 6}{2 \cdot 10} : - \frac{26 + 6}{2}

The solutions to the quadratic equation are:

x = \frac{- 26 + 6}{2}, x = - \frac{26 + 6}{2}

I, P = I^{2} R

y, 4 x y - y - 16 x = 5 x^{2}

3 x^{2} = - 4 x + 3

n (n - 24) = - 128

- 16 x^{2} + 144 x = 0

What are the solutions to the equation x^2+26x+167.5=0 ?
The solutions to the equation x^2+26x+167.5=0 are x=(-26+sqrt(6))/2 ,x=-(26+sqrt(6))/2
Find the zeros of x^2+26x+167.5=0
The zeros of x^2+26x+167.5=0 are x=(-26+sqrt(6))/2 ,x=-(26+sqrt(6))/2