What are the solutions to the equation z^2+25/16 =0 ?

The solutions to the equation z^2+25/16 =0 are z= 5/4 i,z=-5/4 i

Find the zeros of z^2+25/16 =0

The zeros of z^2+25/16 =0 are z= 5/4 i,z=-5/4 i

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z^{2} + \frac{25}{16} = 0

z = \frac{5}{4} i, z = - \frac{5}{4} i

Solution steps

z^{2} + \frac{25}{16} = 0

Move

\frac{25}{16}

to the right side

z^{2} = - \frac{25}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = - \frac{25}{16}, z = - - \frac{25}{16}

- \frac{25}{16} = \frac{5}{4} i

- - \frac{25}{16} = - \frac{5}{4} i

z = \frac{5}{4} i, z = - \frac{5}{4} i

16 t^{2} - 7 t = 17 t - 9

x^{2} - 30 = - x

2 x^{2} = - 7 x + 5

10 x^{2} + x - 21 = 0

(5 x + 1) (x - 2) = 0

What are the solutions to the equation z^2+25/16 =0 ?
The solutions to the equation z^2+25/16 =0 are z= 5/4 i,z=-5/4 i
Find the zeros of z^2+25/16 =0
The zeros of z^2+25/16 =0 are z= 5/4 i,z=-5/4 i