What are the solutions to the equation 3(3x-1)^2+34=46 ?

The solutions to the equation 3(3x-1)^2+34=46 are x=1,x=-1/3

Find the zeros of 3(3x-1)^2+34=46

The zeros of 3(3x-1)^2+34=46 are x=1,x=-1/3

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3 (3 x - 1)^{2} + 34 = 46

x = 1, x = - \frac{1}{3}

Decimal Notation

x = 1, x = - 0.33333 \dots

Solution steps

3 (3 x - 1)^{2} + 34 = 46

Move

34

to the right side

3 (3 x - 1)^{2} = 12

Divide both sides by

3

(3 x - 1)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 1 = 4 : x = 1

Solve

3 x - 1 = - 4 : x = - \frac{1}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{3}

3 x^{2} + 1 = - 25 x - 7

x, a^{2} x^{2} + (a y - a) x = 2 + 2 y

5 x^{2} - 10 x + 8 = 0

2 x^{2} - 1

4 x^{2} - 16 x + 16 = 16 x - 32

What are the solutions to the equation 3(3x-1)^2+34=46 ?
The solutions to the equation 3(3x-1)^2+34=46 are x=1,x=-1/3
Find the zeros of 3(3x-1)^2+34=46
The zeros of 3(3x-1)^2+34=46 are x=1,x=-1/3