What are the solutions to the equation 2x^2=x^2+81 ?

The solutions to the equation 2x^2=x^2+81 are x=9,x=-9

Find the zeros of 2x^2=x^2+81

The zeros of 2x^2=x^2+81 are x=9,x=-9

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2 x^{2} = x^{2} + 81

x = 9, x = - 9

Solution steps

2 x^{2} = x^{2} + 81

Move

x^{2}

to the left side

x^{2} = 81

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 81, x = - 81

81 = 9

- 81 = - 9

x = 9, x = - 9

n^{2} + 1 = - 10

- 5 x^{2} + 35 x - 50 = 0

- \frac{1}{4} x (x - 24) = 0

8 x^{2} + 12 x + 4 = 0

a^{2} = 1, a^{6} = 9

What are the solutions to the equation 2x^2=x^2+81 ?
The solutions to the equation 2x^2=x^2+81 are x=9,x=-9
Find the zeros of 2x^2=x^2+81
The zeros of 2x^2=x^2+81 are x=9,x=-9