What are the solutions to the equation -x-x^2=0 ?

The solutions to the equation -x-x^2=0 are x=-1,x=0

Find the zeros of -x-x^2=0

The zeros of -x-x^2=0 are x=-1,x=0

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- x - x^{2} = 0

x = - 1, x = 0

Solution steps

- x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 1}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 1}{2 ( - 1 )} : - 1

x = \frac{- ( - 1 ) - 1}{2 ( - 1 )} : 0

The solutions to the quadratic equation are:

x = - 1, x = 0

x^{2} + 4 x = 12

6 x^{2} - 35 = 11 x

y, 4 x^{2} - y^{2} = 0

a^{2} + 9 = 9

11 y^{2} - 12 y + 4 = 6 y^{2}

What are the solutions to the equation -x-x^2=0 ?
The solutions to the equation -x-x^2=0 are x=-1,x=0
Find the zeros of -x-x^2=0
The zeros of -x-x^2=0 are x=-1,x=0