What are the solutions to the equation 7(x-4)^2-2=54 ?

The solutions to the equation 7(x-4)^2-2=54 are x=2sqrt(2)+4,x=-2sqrt(2)+4

Find the zeros of 7(x-4)^2-2=54

The zeros of 7(x-4)^2-2=54 are x=2sqrt(2)+4,x=-2sqrt(2)+4

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7 (x - 4)^{2} - 2 = 54

x = 22 + 4, x = - 22 + 4

Decimal Notation

x = 6.82842 \dots, x = 1.17157 \dots

Solution steps

7 (x - 4)^{2} - 2 = 54

Move

2

to the right side

7 (x - 4)^{2} = 56

Divide both sides by

7

(x - 4)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 8 : x = 22 + 4

Solve

x - 4 = - 8 : x = - 22 + 4

The solutions to the quadratic equation are:

x = 22 + 4, x = - 22 + 4

3 b^{2} - 10 b - 8 = 0

x, k x^{2} + 36 x + k = 0

2 x^{2} = 11 x - 20

- 9 x^{2} - 18 x - 2 = 0

y, x^{2} - 2 x y + 1 - 3 y^{2} = 0

What are the solutions to the equation 7(x-4)^2-2=54 ?
The solutions to the equation 7(x-4)^2-2=54 are x=2sqrt(2)+4,x=-2sqrt(2)+4
Find the zeros of 7(x-4)^2-2=54
The zeros of 7(x-4)^2-2=54 are x=2sqrt(2)+4,x=-2sqrt(2)+4