What are the solutions to the equation 0.01x^2-2x+4=0 ?

The solutions to the equation 0.01x^2-2x+4=0 are x=20(5+2sqrt(6)),x=20(5-2sqrt(6))

Find the zeros of 0.01x^2-2x+4=0

The zeros of 0.01x^2-2x+4=0 are x=20(5+2sqrt(6)),x=20(5-2sqrt(6))

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0.01 x^{2} - 2 x + 4 = 0

x = 20 (5 + 26), x = 20 (5 - 26)

Decimal Notation

x = 197.97958 \dots, x = 2.02041 \dots

Solution steps

0.01 x^{2} - 2 x + 4 = 0

Multiply both sides by

100

x^{2} - 200 x + 400 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 200 ) \pm ( - 200 ) ^{2} - 4 \cdot 1 \cdot 400}{2 \cdot 1}

(- 200)^{2} - 4 \cdot 1 \cdot 400 = 806

x_{1, 2} = \frac{- ( - 200 ) \pm 80 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 200 ) + 80 6}{2 \cdot 1}, x_{2} = \frac{- ( - 200 ) - 80 6}{2 \cdot 1}

x = \frac{- ( - 200 ) + 80 6}{2 \cdot 1} : 20 (5 + 26)

x = \frac{- ( - 200 ) - 80 6}{2 \cdot 1} : 20 (5 - 26)

The solutions to the quadratic equation are:

x = 20 (5 + 26), x = 20 (5 - 26)

x, x^{2} + y^{2} = a

\frac{( x + 6 ) ^{2}}{2} = 8

- 6 x^{2} + 48 x - 72 = 0

n^{2} - 10 n + 22 = - 2

x^{2} - 14 x = - 58

What are the solutions to the equation 0.01x^2-2x+4=0 ?
The solutions to the equation 0.01x^2-2x+4=0 are x=20(5+2sqrt(6)),x=20(5-2sqrt(6))
Find the zeros of 0.01x^2-2x+4=0
The zeros of 0.01x^2-2x+4=0 are x=20(5+2sqrt(6)),x=20(5-2sqrt(6))