What are the solutions to the equation 0=5x^2+x+1 ?

The solutions to the equation 0=5x^2+x+1 are x=-1/10+i(sqrt(19))/(10),x=-1/10-i(sqrt(19))/(10)

Find the zeros of 0=5x^2+x+1

The zeros of 0=5x^2+x+1 are x=-1/10+i(sqrt(19))/(10),x=-1/10-i(sqrt(19))/(10)

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0 = 5 x^{2} + x + 1

x = - \frac{1}{10} + i \frac{19}{10}, x = - \frac{1}{10} - i \frac{19}{10}

Solution steps

0 = 5 x^{2} + x + 1

Switch sides

5 x^{2} + x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

Simplify

1^{2} - 4 \cdot 5 \cdot 1 : 19 i

x_{1, 2} = \frac{- 1 \pm 19 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 1 + 19 i}{2 \cdot 5}, x_{2} = \frac{- 1 - 19 i}{2 \cdot 5}

x = \frac{- 1 + 19 i}{2 \cdot 5} : - \frac{1}{10} + i \frac{19}{10}

x = \frac{- 1 - 19 i}{2 \cdot 5} : - \frac{1}{10} - i \frac{19}{10}

The solutions to the quadratic equation are:

x = - \frac{1}{10} + i \frac{19}{10}, x = - \frac{1}{10} - i \frac{19}{10}

3 x^{2} + 2 x - 1

- \frac{1}{3} x - 6 = - 3

5 x - 11 = 2 x + 16

\frac{c ^{\frac{2}{3}} d ^{- 5}}{c ^{\frac{1}{6}} d ^{- 1}}

7 + \frac{1}{5}

What are the solutions to the equation 0=5x^2+x+1 ?
The solutions to the equation 0=5x^2+x+1 are x=-1/10+i(sqrt(19))/(10),x=-1/10-i(sqrt(19))/(10)
Find the zeros of 0=5x^2+x+1
The zeros of 0=5x^2+x+1 are x=-1/10+i(sqrt(19))/(10),x=-1/10-i(sqrt(19))/(10)