What are the solutions to the equation -2*x^2+11*x+c=0 ?

The solutions to the equation -2*x^2+11*x+c=0 are x=-(-11+sqrt(121+8c))/4 ,x=-(-11-sqrt(121+8c))/4

Find the zeros of -2*x^2+11*x+c=0

The zeros of -2*x^2+11*x+c=0 are x=-(-11+sqrt(121+8c))/4 ,x=-(-11-sqrt(121+8c))/4

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- 2 \cdot x^{2} + 11 \cdot x + c = 0

x = - \frac{- 11 + 121 + 8 c}{4}, x = - \frac{- 11 - 121 + 8 c}{4}

Solution steps

- 2 x^{2} + 11 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 ( - 2 ) c}{2 ( - 2 )}

Simplify

1 1^{2} - 4 (- 2) c : 121 + 8 c

x_{1, 2} = \frac{- 11 \pm 121 + 8 c}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 11 + 121 + 8 c}{2 ( - 2 )}, x_{2} = \frac{- 11 - 121 + 8 c}{2 ( - 2 )}

x = \frac{- 11 + 121 + 8 c}{2 ( - 2 )} : - \frac{- 11 + 121 + 8 c}{4}

x = \frac{- 11 - 121 + 8 c}{2 ( - 2 )} : - \frac{- 11 - 121 + 8 c}{4}

The solutions to the quadratic equation are:

x = - \frac{- 11 + 121 + 8 c}{4}, x = - \frac{- 11 - 121 + 8 c}{4}

(2 x + 10) (x - 4) = 0

x^{2} - 10 x + 25 = 0

3 x^{2} + 18 x = - 18

x^{2} - x - 1 = 0

(2 x - 1)^{2} = - x^{2} - 12 x + 5

What are the solutions to the equation -2*x^2+11*x+c=0 ?
The solutions to the equation -2*x^2+11*x+c=0 are x=-(-11+sqrt(121+8c))/4 ,x=-(-11-sqrt(121+8c))/4
Find the zeros of -2*x^2+11*x+c=0
The zeros of -2*x^2+11*x+c=0 are x=-(-11+sqrt(121+8c))/4 ,x=-(-11-sqrt(121+8c))/4