What are the solutions to the equation 0=2x^2-8x ?

The solutions to the equation 0=2x^2-8x are x=4,x=0

Find the zeros of 0=2x^2-8x

The zeros of 0=2x^2-8x are x=4,x=0

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0 = 2 x^{2} - 8 x

x = 4, x = 0

Solution steps

0 = 2 x^{2} - 8 x

Switch sides

2 x^{2} - 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 \cdot 0 = 8

x_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 2}

x = \frac{- ( - 8 ) + 8}{2 \cdot 2} : 4

x = \frac{- ( - 8 ) - 8}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 4, x = 0

10 n^{2} + 15 n - 25 = 6 n^{2}

x, z = 2 x^{2} - 4 y^{2}

\times (- 16) y^{2} = 0

x^{2} + 50 x - 30000 = 0

9 (x^{2} - 13) + 9 = - 8

What are the solutions to the equation 0=2x^2-8x ?
The solutions to the equation 0=2x^2-8x are x=4,x=0
Find the zeros of 0=2x^2-8x
The zeros of 0=2x^2-8x are x=4,x=0