What are the solutions to the equation 4x^2+56x+144=0 ?

The solutions to the equation 4x^2+56x+144=0 are x=-7+sqrt(13),x=-7-sqrt(13)

Find the zeros of 4x^2+56x+144=0

The zeros of 4x^2+56x+144=0 are x=-7+sqrt(13),x=-7-sqrt(13)

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4 x^{2} + 56 x + 144 = 0

x = - 7 + 13, x = - 7 - 13

Decimal

x = - 3.39444 \dots, x = - 10.60555 \dots

Solution steps

4 x^{2} + 56 x + 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 56 \pm 5 6 ^{2} - 4 \cdot 4 \cdot 144}{2 \cdot 4}

5 6^{2} - 4 \cdot 4 \cdot 144 = 813

x_{1, 2} = \frac{- 56 \pm 8 13}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 56 + 8 13}{2 \cdot 4}, x_{2} = \frac{- 56 - 8 13}{2 \cdot 4}

x = \frac{- 56 + 8 13}{2 \cdot 4} : - 7 + 13

x = \frac{- 56 - 8 13}{2 \cdot 4} : - 7 - 13

The solutions to the quadratic equation are:

x = - 7 + 13, x = - 7 - 13

x^{2} + 6 x + 3 = - x (x - 1)

(\frac{16}{9}) x^{2} = 64

x, 3 x^{2} - 2 + 2 s in x = 0

3 x^{2} - 16 x + 3 = 0

5 r^{2} - 7 r + 4 = 6

What are the solutions to the equation 4x^2+56x+144=0 ?
The solutions to the equation 4x^2+56x+144=0 are x=-7+sqrt(13),x=-7-sqrt(13)
Find the zeros of 4x^2+56x+144=0
The zeros of 4x^2+56x+144=0 are x=-7+sqrt(13),x=-7-sqrt(13)