What are the solutions to the equation (12x+18)(1.6-0.2x)=0 ?

The solutions to the equation (12x+18)(1.6-0.2x)=0 are x=-3/2 ,x=8

Find the zeros of (12x+18)(1.6-0.2x)=0

The zeros of (12x+18)(1.6-0.2x)=0 are x=-3/2 ,x=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(12 x + 18) (1.6 - 0.2 x) = 0

x = - \frac{3}{2}, x = 8

Decimal Notation

x = - 1.5, x = 8

Solution steps

(12 x + 18) (1.6 - 0.2 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

12 x + 18 = 0 or 1.6 - 0.2 x = 0

Solve

12 x + 18 = 0 : x = - \frac{3}{2}

Solve

1.6 - 0.2 x = 0 : x = 8

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 8

7 m + m^{2} + 10 = 0

3 x^{2} + \frac{9}{2} x - 4 = 5 x + \frac{3}{4}

y, x + x y + 2 y^{2} = 6

2 x^{2} - 20 x + 58

3 x^{2} - 6 x + 9

What are the solutions to the equation (12x+18)(1.6-0.2x)=0 ?
The solutions to the equation (12x+18)(1.6-0.2x)=0 are x=-3/2 ,x=8
Find the zeros of (12x+18)(1.6-0.2x)=0
The zeros of (12x+18)(1.6-0.2x)=0 are x=-3/2 ,x=8