What are the solutions to the equation 4.1x^2+3x-50=0 ?

The solutions to the equation 4.1x^2+3x-50=0 are x=(5(sqrt(829)-3))/(41),x=-(5(3+sqrt(829)))/(41)

Find the zeros of 4.1x^2+3x-50=0

The zeros of 4.1x^2+3x-50=0 are x=(5(sqrt(829)-3))/(41),x=-(5(3+sqrt(829)))/(41)

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4.1 x^{2} + 3 x - 50 = 0

x = \frac{5 ( 829 - 3 )}{41}, x = - \frac{5 ( 3 + 829 )}{41}

Decimal Notation

x = 3.14540 \dots, x = - 3.87711 \dots

Solution steps

4.1 x^{2} + 3 x - 50 = 0

Multiply both sides by

10

41 x^{2} + 30 x - 500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 \cdot 41 ( - 500 )}{2 \cdot 41}

3 0^{2} - 4 \cdot 41 (- 500) = 10829

x_{1, 2} = \frac{- 30 \pm 10 829}{2 \cdot 41}

Separate the solutions

x_{1} = \frac{- 30 + 10 829}{2 \cdot 41}, x_{2} = \frac{- 30 - 10 829}{2 \cdot 41}

x = \frac{- 30 + 10 829}{2 \cdot 41} : \frac{5 ( 829 - 3 )}{41}

x = \frac{- 30 - 10 829}{2 \cdot 41} : - \frac{5 ( 3 + 829 )}{41}

The solutions to the quadratic equation are:

x = \frac{5 ( 829 - 3 )}{41}, x = - \frac{5 ( 3 + 829 )}{41}

0 = 4 x + x^{2}

2 q^{2} + 6 q - 5 = 0

2 x^{2} + 72 x - 504 = 0

4 x^{2} + 48 x = 288

4 (x - 1)^{2} = 25

What are the solutions to the equation 4.1x^2+3x-50=0 ?
The solutions to the equation 4.1x^2+3x-50=0 are x=(5(sqrt(829)-3))/(41),x=-(5(3+sqrt(829)))/(41)
Find the zeros of 4.1x^2+3x-50=0
The zeros of 4.1x^2+3x-50=0 are x=(5(sqrt(829)-3))/(41),x=-(5(3+sqrt(829)))/(41)