What are the solutions to the equation x^2-4/5 x+16/25 =0 ?

The solutions to the equation x^2-4/5 x+16/25 =0 are x= 2/5+i(2sqrt(3))/5 ,x= 2/5-i(2sqrt(3))/5

Find the zeros of x^2-4/5 x+16/25 =0

The zeros of x^2-4/5 x+16/25 =0 are x= 2/5+i(2sqrt(3))/5 ,x= 2/5-i(2sqrt(3))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - \frac{4}{5} x + \frac{16}{25} = 0

x = \frac{2}{5} + i \frac{2 3}{5}, x = \frac{2}{5} - i \frac{2 3}{5}

Solution steps

x^{2} - \frac{4}{5} x + \frac{16}{25} = 0

Find Least Common Multiplier of

5, 25 : 25

Multiply by LCM=

25

x^{2} \cdot 25 - \frac{4}{5} x \cdot 25 + \frac{16}{25} \cdot 25 = 0 \cdot 25

Simplify

25 x^{2} - 20 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 25 \cdot 16}{2 \cdot 25}

Simplify

(- 20)^{2} - 4 \cdot 25 \cdot 16 : 203 i

x_{1, 2} = \frac{- ( - 20 ) \pm 20 3 i}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 20 3 i}{2 \cdot 25}, x_{2} = \frac{- ( - 20 ) - 20 3 i}{2 \cdot 25}

x = \frac{- ( - 20 ) + 20 3 i}{2 \cdot 25} : \frac{2}{5} + i \frac{2 3}{5}

x = \frac{- ( - 20 ) - 20 3 i}{2 \cdot 25} : \frac{2}{5} - i \frac{2 3}{5}

The solutions to the quadratic equation are:

x = \frac{2}{5} + i \frac{2 3}{5}, x = \frac{2}{5} - i \frac{2 3}{5}

20 b^{2} - 125 = 0

x^{2} - 1 = - 8

p^{2} - p - 30 = 0

r^{2} - 6 r - 16 = - 5

4 x^{2} + 18 x + 17 = 0

What are the solutions to the equation x^2-4/5 x+16/25 =0 ?
The solutions to the equation x^2-4/5 x+16/25 =0 are x= 2/5+i(2sqrt(3))/5 ,x= 2/5-i(2sqrt(3))/5
Find the zeros of x^2-4/5 x+16/25 =0
The zeros of x^2-4/5 x+16/25 =0 are x= 2/5+i(2sqrt(3))/5 ,x= 2/5-i(2sqrt(3))/5