What are the solutions to the equation (3x)/8-(x^2)/8 =0 ?

The solutions to the equation (3x)/8-(x^2)/8 =0 are x=0,x=3

Find the zeros of (3x)/8-(x^2)/8 =0

The zeros of (3x)/8-(x^2)/8 =0 are x=0,x=3

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\frac{3 x}{8} - \frac{x ^{2}}{8} = 0

x = 0, x = 3

Solution steps

\frac{3 x}{8} - \frac{x ^{2}}{8} = 0

Multiply both sides by

8

- x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 ( - 1 )}, x_{2} = \frac{- 3 - 3}{2 ( - 1 )}

x = \frac{- 3 + 3}{2 ( - 1 )} : 0

x = \frac{- 3 - 3}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = 0, x = 3

x^{2} + 36 x + 332 = 0

x^{2} + 7 x - 18 = 0

13 x^{2} - 27 = 0

2 x^{2} + 5 = 4 x

2 x^{2} + 13 x + 8 = 0

What are the solutions to the equation (3x)/8-(x^2)/8 =0 ?
The solutions to the equation (3x)/8-(x^2)/8 =0 are x=0,x=3
Find the zeros of (3x)/8-(x^2)/8 =0
The zeros of (3x)/8-(x^2)/8 =0 are x=0,x=3