What are the solutions to the equation roots 4x^2+1 ?

The solutions to the equation roots 4x^2+1 are x= 1/2 i,x=-1/2 i

Find the zeros of roots 4x^2+1

The zeros of roots 4x^2+1 are x= 1/2 i,x=-1/2 i

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roots

4 x^{2} + 1

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

4 x^{2} + 1

The roots are the intercepts with the x-axis

(y = 0)

4 x^{2} + 1 = 0

Move

1

to the right side

4 x^{2} = - 1

Divide both sides by

4

x^{2} = - \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{4}, x = - - \frac{1}{4}

- \frac{1}{4} = \frac{1}{2} i

- - \frac{1}{4} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

x^{2} + 8 x = 9

5 x^{2} + 15 x = 40

0 = 0.5 F (1 - \frac{F}{3000})

5 x^{2} + 8 x - 3 = 1

16 (x^{2} - 4) - 5 = 12

What are the solutions to the equation roots 4x^2+1 ?
The solutions to the equation roots 4x^2+1 are x= 1/2 i,x=-1/2 i
Find the zeros of roots 4x^2+1
The zeros of roots 4x^2+1 are x= 1/2 i,x=-1/2 i