What are the solutions to the equation r^2-6r-16=-5 ?

The solutions to the equation r^2-6r-16=-5 are r=3+2sqrt(5),r=3-2sqrt(5)

Find the zeros of r^2-6r-16=-5

The zeros of r^2-6r-16=-5 are r=3+2sqrt(5),r=3-2sqrt(5)

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r^{2} - 6 r - 16 = - 5

r = 3 + 25, r = 3 - 25

Decimal Notation

r = 7.47213 \dots, r = - 1.47213 \dots

Solution steps

r^{2} - 6 r - 16 = - 5

Move

5

to the left side

r^{2} - 6 r - 11 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 11) = 45

r_{1, 2} = \frac{- ( - 6 ) \pm 4 5}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 6 ) + 4 5}{2 \cdot 1}, r_{2} = \frac{- ( - 6 ) - 4 5}{2 \cdot 1}

r = \frac{- ( - 6 ) + 4 5}{2 \cdot 1} : 3 + 25

r = \frac{- ( - 6 ) - 4 5}{2 \cdot 1} : 3 - 25

The solutions to the quadratic equation are:

r = 3 + 25, r = 3 - 25

0 = 3 x^{2} - 16 x + 24

4.9 x^{2} - 6 x - 20 = 0

x^{2} + 2 x - 35 = 0

y, χ y^{2} z^{3} = 2

0 = - 3 x^{2} + 4

What are the solutions to the equation r^2-6r-16=-5 ?
The solutions to the equation r^2-6r-16=-5 are r=3+2sqrt(5),r=3-2sqrt(5)
Find the zeros of r^2-6r-16=-5
The zeros of r^2-6r-16=-5 are r=3+2sqrt(5),r=3-2sqrt(5)