What are the solutions to the equation 12x^2+16x=0 ?

The solutions to the equation 12x^2+16x=0 are x=0,x=-4/3

Find the zeros of 12x^2+16x=0

The zeros of 12x^2+16x=0 are x=0,x=-4/3

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12 x^{2} + 16 x = 0

x = 0, x = - \frac{4}{3}

Decimal Notation

x = 0, x = - 1.33333 \dots

Solution steps

12 x^{2} + 16 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 12 \cdot 0}{2 \cdot 12}

1 6^{2} - 4 \cdot 12 \cdot 0 = 16

x_{1, 2} = \frac{- 16 \pm 16}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 16 + 16}{2 \cdot 12}, x_{2} = \frac{- 16 - 16}{2 \cdot 12}

x = \frac{- 16 + 16}{2 \cdot 12} : 0

x = \frac{- 16 - 16}{2 \cdot 12} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{4}{3}

3 x^{2} + x + 4 = - 9 x + 1

x, 61 x^{2} - 20 x - 32 = 0

12 x^{2} - 17 x - 6 = 7 x^{2} + 6

y, x + y^{2} = 2

x, x^{2} - y^{2} = z

What are the solutions to the equation 12x^2+16x=0 ?
The solutions to the equation 12x^2+16x=0 are x=0,x=-4/3
Find the zeros of 12x^2+16x=0
The zeros of 12x^2+16x=0 are x=0,x=-4/3