What are the solutions to the equation 144t-16t^2=320 ?

The solutions to the equation 144t-16t^2=320 are t=4,t=5

Find the zeros of 144t-16t^2=320

The zeros of 144t-16t^2=320 are t=4,t=5

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144 t - 16 t^{2} = 320

t = 4, t = 5

Solution steps

144 t - 16 t^{2} = 320

Move

320

to the left side

144 t - 16 t^{2} - 320 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 t^{2} + 144 t - 320 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 144 \pm 14 4 ^{2} - 4 ( - 16 ) ( - 320 )}{2 ( - 16 )}

14 4^{2} - 4 (- 16) (- 320) = 16

t_{1, 2} = \frac{- 144 \pm 16}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 144 + 16}{2 ( - 16 )}, t_{2} = \frac{- 144 - 16}{2 ( - 16 )}

t = \frac{- 144 + 16}{2 ( - 16 )} : 4

t = \frac{- 144 - 16}{2 ( - 16 )} : 5

The solutions to the quadratic equation are:

t = 4, t = 5

x^{2} - 3 x + 4 - 4 = 0

y, x^{2} - y^{3} = 0

20 x + 14 = - 3 x^{2}

2 y (y - 5) = 3 (2 y - 1) - 4

x^{2} - 12 x - 63 = 9

What are the solutions to the equation 144t-16t^2=320 ?
The solutions to the equation 144t-16t^2=320 are t=4,t=5
Find the zeros of 144t-16t^2=320
The zeros of 144t-16t^2=320 are t=4,t=5