What are the solutions to the equation 3x(x-2)=(x-2)(x-6) ?

The solutions to the equation 3x(x-2)=(x-2)(x-6) are x=2,x=-3

Find the zeros of 3x(x-2)=(x-2)(x-6)

The zeros of 3x(x-2)=(x-2)(x-6) are x=2,x=-3

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3 x (x - 2) = (x - 2) (x - 6)

x = 2, x = - 3

Solution steps

3 x (x - 2) = (x - 2) (x - 6)

Move

(x - 2) (x - 6)

to the left side

3 x (x - 2) - (x - 2) (x - 6) = 0

Factor

3 x (x - 2) - (x - 2) (x - 6) : 2 (x - 2) (x + 3)

2 (x - 2) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 3 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = 2, x = - 3

- 2 x^{2} - x = 6

y, U = X^{3} + 3 X y^{2}

\frac{x ^{2}}{2} = \frac{2 x}{4}

12 = 10 t + \frac{1}{2} (- 3.7) t^{2}

y, x^{2} y = 5

What are the solutions to the equation 3x(x-2)=(x-2)(x-6) ?
The solutions to the equation 3x(x-2)=(x-2)(x-6) are x=2,x=-3
Find the zeros of 3x(x-2)=(x-2)(x-6)
The zeros of 3x(x-2)=(x-2)(x-6) are x=2,x=-3