What are the solutions to the equation factor x^2+7x+3=3 ?

The solutions to the equation factor x^2+7x+3=3 are x=0,x=-7

Find the zeros of factor x^2+7x+3=3

The zeros of factor x^2+7x+3=3 are x=0,x=-7

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x^{2} + 7 x + 3 = 3

x = 0, x = - 7

Solution steps

x^{2} + 7 x + 3 = 3

Move

3

to the right side

x^{2} + 7 x = 0

Factor

x^{2} + 7 x : x (x + 7)

x (x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 7 = 0

Solve

x + 7 = 0 : x = - 7

The solutions to the quadratic equation are:

x = 0, x = - 7

- 4 t^{2} + 32 t = - 132

x^{2} + (4 x + 16)^{2} = (4 x + 17)^{2}

x^{2} + 2 x = 80

x^{2} + 2 x = 15

- 24 = - 3 x^{2} - 6 x

What are the solutions to the equation factor x^2+7x+3=3 ?
The solutions to the equation factor x^2+7x+3=3 are x=0,x=-7
Find the zeros of factor x^2+7x+3=3
The zeros of factor x^2+7x+3=3 are x=0,x=-7