What are the solutions to the equation -2x^2-4x+16=20-x ?

The solutions to the equation -2x^2-4x+16=20-x are x=-3/4-i(sqrt(23))/4 ,x=-3/4+i(sqrt(23))/4

Find the zeros of -2x^2-4x+16=20-x

The zeros of -2x^2-4x+16=20-x are x=-3/4-i(sqrt(23))/4 ,x=-3/4+i(sqrt(23))/4

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- 2 x^{2} - 4 x + 16 = 20 - x

x = - \frac{3}{4} - i \frac{23}{4}, x = - \frac{3}{4} + i \frac{23}{4}

Solution steps

- 2 x^{2} - 4 x + 16 = 20 - x

Move

x

to the left side

- 2 x^{2} - 3 x + 16 = 20

Move

20

to the left side

- 2 x^{2} - 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 2 ) ( - 4 )}{2 ( - 2 )}

Simplify

(- 3)^{2} - 4 (- 2) (- 4) : 23 i

x_{1, 2} = \frac{- ( - 3 ) \pm 23 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 23 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 3 ) - 23 i}{2 ( - 2 )}

x = \frac{- ( - 3 ) + 23 i}{2 ( - 2 )} : - \frac{3}{4} - i \frac{23}{4}

x = \frac{- ( - 3 ) - 23 i}{2 ( - 2 )} : - \frac{3}{4} + i \frac{23}{4}

The solutions to the quadratic equation are:

x = - \frac{3}{4} - i \frac{23}{4}, x = - \frac{3}{4} + i \frac{23}{4}

6 u^{2} - 2 u = 0

y, x^{2} - 2 x y + y^{2} - 6 x - 6 y + 3 = 0

x^{2} - 6 = - 5

2 x^{2} - 4 = - 7 x

- x^{2} + 22 x + 104 = 0

What are the solutions to the equation -2x^2-4x+16=20-x ?
The solutions to the equation -2x^2-4x+16=20-x are x=-3/4-i(sqrt(23))/4 ,x=-3/4+i(sqrt(23))/4
Find the zeros of -2x^2-4x+16=20-x
The zeros of -2x^2-4x+16=20-x are x=-3/4-i(sqrt(23))/4 ,x=-3/4+i(sqrt(23))/4