What are the solutions to the equation roots 2x^2-x-1 ?

The solutions to the equation roots 2x^2-x-1 are x=1,x=-1/2

Find the zeros of roots 2x^2-x-1

The zeros of roots 2x^2-x-1 are x=1,x=-1/2

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roots

2 x^{2} - x - 1

x = 1, x = - \frac{1}{2}

Solution steps

2 x^{2} - x - 1

The roots are the intercepts with the x-axis

(y = 0)

2 x^{2} - x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 1) = 3

x_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 2}

x = \frac{- ( - 1 ) + 3}{2 \cdot 2} : 1

x = \frac{- ( - 1 ) - 3}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{2}

16 n^{2} = 25

y, (x + 2)^{2} + (y - 4)^{2} = - 12

240 = 128 t - 16 t^{2}

y, y^{2} = 4 x^{2} + x^{3} - 36 - 9 x

x, 81 x^{2} + 72 x + 28 = 0

What are the solutions to the equation roots 2x^2-x-1 ?
The solutions to the equation roots 2x^2-x-1 are x=1,x=-1/2
Find the zeros of roots 2x^2-x-1
The zeros of roots 2x^2-x-1 are x=1,x=-1/2