What are the solutions to the equation 9x^2+6x-2=0 ?

The solutions to the equation 9x^2+6x-2=0 are x=(-1+sqrt(3))/3 ,x=-(1+sqrt(3))/3

Find the zeros of 9x^2+6x-2=0

The zeros of 9x^2+6x-2=0 are x=(-1+sqrt(3))/3 ,x=-(1+sqrt(3))/3

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9 x^{2} + 6 x - 2 = 0

x = \frac{- 1 + 3}{3}, x = - \frac{1 + 3}{3}

Decimal Notation

x = 0.24401 \dots, x = - 0.91068 \dots

Solution steps

9 x^{2} + 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 ( - 2 )}{2 \cdot 9}

6^{2} - 4 \cdot 9 (- 2) = 63

x_{1, 2} = \frac{- 6 \pm 6 3}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 6 + 6 3}{2 \cdot 9}, x_{2} = \frac{- 6 - 6 3}{2 \cdot 9}

x = \frac{- 6 + 6 3}{2 \cdot 9} : \frac{- 1 + 3}{3}

x = \frac{- 6 - 6 3}{2 \cdot 9} : - \frac{1 + 3}{3}

The solutions to the quadratic equation are:

x = \frac{- 1 + 3}{3}, x = - \frac{1 + 3}{3}

x (x + 21) = 100

- 7 (x + 5) = x^{2} + (5 - a) x - 5 a

y, (3 x - y)^{2} + (x - 5)^{2} = 0

4 x^{2} + 12 x = - 3

2 x^{2} = 8

What are the solutions to the equation 9x^2+6x-2=0 ?
The solutions to the equation 9x^2+6x-2=0 are x=(-1+sqrt(3))/3 ,x=-(1+sqrt(3))/3
Find the zeros of 9x^2+6x-2=0
The zeros of 9x^2+6x-2=0 are x=(-1+sqrt(3))/3 ,x=-(1+sqrt(3))/3