What are the solutions to the equation s^2+8s+160=0 ?

The solutions to the equation s^2+8s+160=0 are s=-4+12i,s=-4-12i

Find the zeros of s^2+8s+160=0

The zeros of s^2+8s+160=0 are s=-4+12i,s=-4-12i

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s^{2} + 8 s + 160 = 0

s = - 4 + 12 i, s = - 4 - 12 i

Solution steps

s^{2} + 8 s + 160 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 160}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 160 : 24 i

s_{1, 2} = \frac{- 8 \pm 24 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 8 + 24 i}{2 \cdot 1}, s_{2} = \frac{- 8 - 24 i}{2 \cdot 1}

s = \frac{- 8 + 24 i}{2 \cdot 1} : - 4 + 12 i

s = \frac{- 8 - 24 i}{2 \cdot 1} : - 4 - 12 i

The solutions to the quadratic equation are:

s = - 4 + 12 i, s = - 4 - 12 i

u^{2} = - 15 u

x^{2} + 31 = - 12 x

2 x^{2} - 2 x + 1

x, (f xg) = x - 3 + x^{2}

(x - 5) (2 x + 3) = 0

What are the solutions to the equation s^2+8s+160=0 ?
The solutions to the equation s^2+8s+160=0 are s=-4+12i,s=-4-12i
Find the zeros of s^2+8s+160=0
The zeros of s^2+8s+160=0 are s=-4+12i,s=-4-12i