What are the solutions to the equation -3y^2=-48 ?

The solutions to the equation -3y^2=-48 are y=4,y=-4

Find the zeros of -3y^2=-48

The zeros of -3y^2=-48 are y=4,y=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 y^{2} = - 48

y = 4, y = - 4

Solution steps

- 3 y^{2} = - 48

Divide both sides by

- 3

y^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 16, y = - 16

16 = 4

- 16 = - 4

y = 4, y = - 4

3 - ∣ 2 x + 6 ∣ = 1

- 0.08 x + 1.1 = - 3.2 x - 5.14

49 p^{2} - 28 p - 5

3 p = - 39

20 = \frac{n}{4}

What are the solutions to the equation -3y^2=-48 ?
The solutions to the equation -3y^2=-48 are y=4,y=-4
Find the zeros of -3y^2=-48
The zeros of -3y^2=-48 are y=4,y=-4