What are the solutions to the equation roots x^2-6x+k ?

The solutions to the equation roots x^2-6x+k are x=3+sqrt(-k+9),x=3-sqrt(-k+9)

Find the zeros of roots x^2-6x+k

The zeros of roots x^2-6x+k are x=3+sqrt(-k+9),x=3-sqrt(-k+9)

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roots

x^{2} - 6 x + k

x = 3 + - k + 9, x = 3 - - k + 9

Solution steps

x^{2} - 6 x + k

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 6 x + k = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot k}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot k : 2 9 - k

x_{1, 2} = \frac{- ( - 6 ) \pm 2 9 - k}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 9 - k}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 9 - k}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 9 - k}{2 \cdot 1} : 3 + - k + 9

x = \frac{- ( - 6 ) - 2 9 - k}{2 \cdot 1} : 3 - - k + 9

The solutions to the quadratic equation are:

x = 3 + - k + 9, x = 3 - - k + 9

x^{2} + 8 = 35 - 6 x

r^{2} - 6 r + 19 = 6 r

0 = 3 x^{2} - 10 x + 6

3 x^{2} - 8 n + 4

x^{2} + 12 x + 23 = 0

What are the solutions to the equation roots x^2-6x+k ?
The solutions to the equation roots x^2-6x+k are x=3+sqrt(-k+9),x=3-sqrt(-k+9)
Find the zeros of roots x^2-6x+k
The zeros of roots x^2-6x+k are x=3+sqrt(-k+9),x=3-sqrt(-k+9)