What are the solutions to the equation 7x^2+5x=4x^2-x ?

The solutions to the equation 7x^2+5x=4x^2-x are x=0,x=-2

Find the zeros of 7x^2+5x=4x^2-x

The zeros of 7x^2+5x=4x^2-x are x=0,x=-2

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7 x^{2} + 5 x = 4 x^{2} - x

x = 0, x = - 2

Solution steps

7 x^{2} + 5 x = 4 x^{2} - x

Move

x

to the left side

7 x^{2} + 6 x = 4 x^{2}

Move

4 x^{2}

to the left side

3 x^{2} + 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

6^{2} - 4 \cdot 3 \cdot 0 = 6

x_{1, 2} = \frac{- 6 \pm 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 6}{2 \cdot 3}, x_{2} = \frac{- 6 - 6}{2 \cdot 3}

x = \frac{- 6 + 6}{2 \cdot 3} : 0

x = \frac{- 6 - 6}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

4 (5 x + 8)^{2} - 23 = 13

\frac{1}{2} d^{2} + 4 d = - 12

y, 2 x^{2} - 3 x y + y^{2} - x + 2 y = 8

3 q^{2} - 90 q + 600 = 0

16 (x^{2} - 5) + 14 = 15

What are the solutions to the equation 7x^2+5x=4x^2-x ?
The solutions to the equation 7x^2+5x=4x^2-x are x=0,x=-2
Find the zeros of 7x^2+5x=4x^2-x
The zeros of 7x^2+5x=4x^2-x are x=0,x=-2