What are the solutions to the equation (2x+2)(x+1)=0 ?

The solutions to the equation (2x+2)(x+1)=0 are x=-1

Find the zeros of (2x+2)(x+1)=0

The zeros of (2x+2)(x+1)=0 are x=-1

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(2 x + 2) (x + 1) = 0

x = - 1

Solution steps

(2 x + 2) (x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 2 = 0 or x + 1 = 0

Solve

2 x + 2 = 0 : x = - 1

Solve

x + 1 = 0 : x = - 1

The solution to the quadratic equation is:

x = - 1

- 3 x^{2} - 3 x + 18 = 0

- x^{2} + 4 = - 4 x + 8

2 x^{2} + 8 x + 80 = 0

x, r (x)^{2} = x^{2} + y^{2}

x^{2} + 14 x + 45 = 0

What are the solutions to the equation (2x+2)(x+1)=0 ?
The solutions to the equation (2x+2)(x+1)=0 are x=-1
Find the zeros of (2x+2)(x+1)=0
The zeros of (2x+2)(x+1)=0 are x=-1