What are the solutions to the equation 3a^2-14a+12=0 ?

The solutions to the equation 3a^2-14a+12=0 are a=(7+sqrt(13))/3 ,a=(7-sqrt(13))/3

Find the zeros of 3a^2-14a+12=0

The zeros of 3a^2-14a+12=0 are a=(7+sqrt(13))/3 ,a=(7-sqrt(13))/3

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3 a^{2} - 14 a + 12 = 0

a = \frac{7 + 13}{3}, a = \frac{7 - 13}{3}

Decimal Notation

a = 3.53518 \dots, a = 1.13148 \dots

Solution steps

3 a^{2} - 14 a + 12 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

(- 14)^{2} - 4 \cdot 3 \cdot 12 = 213

a_{1, 2} = \frac{- ( - 14 ) \pm 2 13}{2 \cdot 3}

Separate the solutions

a_{1} = \frac{- ( - 14 ) + 2 13}{2 \cdot 3}, a_{2} = \frac{- ( - 14 ) - 2 13}{2 \cdot 3}

a = \frac{- ( - 14 ) + 2 13}{2 \cdot 3} : \frac{7 + 13}{3}

a = \frac{- ( - 14 ) - 2 13}{2 \cdot 3} : \frac{7 - 13}{3}

The solutions to the quadratic equation are:

a = \frac{7 + 13}{3}, a = \frac{7 - 13}{3}

x, x^{2} + 3 t x = c

\frac{1}{2} x^{2} + \frac{3}{8} x = 2

(1 - x) (11 - x) + 26 = 0

8 x^{2} + 3 = 2

x^{2} + 14 x + 6 = 0

What are the solutions to the equation 3a^2-14a+12=0 ?
The solutions to the equation 3a^2-14a+12=0 are a=(7+sqrt(13))/3 ,a=(7-sqrt(13))/3
Find the zeros of 3a^2-14a+12=0
The zeros of 3a^2-14a+12=0 are a=(7+sqrt(13))/3 ,a=(7-sqrt(13))/3